Matematika Sekolah Menengah Atas Lim x→8 [tex]( \frac{x - 8}{ \sqrt[3]{ {x}^{2} } + 5 } )[/tex]tolong bantuannya besok dikumpul​

arjunboganulv – March 08, 2023

Lim x→8
[tex]( \frac{x - 8}{ \sqrt[3]{ {x}^{2} } + 5 } )[/tex]
tolong bantuannya besok dikumpul​

[tex] \displaystyle \tt\lim_{x \to 8} (\frac{x - 8}{ \sqrt[3]{ {x}^{2} + 5}}) [/tex]

[tex] \tt= \frac{8 - 8}{ \sqrt[3]{\displaystyle \tt\lim_{x \to 8} ( {x}^{2}) + \displaystyle \tt\lim_{x \to 8}(5)}}[/tex]

[tex]\tt= \frac{8 - 8}{ \sqrt[3]{\displaystyle(\tt\lim_{x \to 8} (x))^{2} + 5} } [/tex]

[tex] = \tt \frac{8 - 8}{ \sqrt[3]{ {8}^{2} + 5} } [/tex]

[tex] \tt= \frac{0}{\sqrt[3]{{8}^{2} + 5}} [/tex]

[tex] \tt=0[/tex]

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